MFM1P – Oct 16, 2014


I began the class today by checking to see how many students did the homework assigned to them yesterday while I was away.  There were a number of questions the students wanted me to take up so I told them I would take up as many as I could and would then take up the rest of the questions on the digital projector at the start of tomorrow’s class.  I then took up the questions students had from yesterday’s homework.  After taking up the homework questions, I then assigned the homework for the students to work on for the remainder of the period (Pages 38 & 39 #1 – 10).  This homework is a review of sections 1.1 to 1.5 of the textbook which is how much we have covered up to this point in this unit.

Below you will find a copies of the handouts/worksheets that were distributed/assigned in today’s class.

Take-up of the homework from Oct 15 (Page 23 & 24 #3b, 5 & 6)

Electronic Copy of Homework Questions (Students are to do #1 – 10 from this handout which is a review of sections 1.1 to 1.5.  The “practice test” is also on this handout as well for those students that did not complete it for homework yesterday)

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4 Responses to MFM1P – Oct 16, 2014

  1. Dylan C says:

    I don’t understand question 2a and 4 and 10b


    • Mr. Bawa says:

      Hi Dylan,

      For 2a, the 90cm is the length of the square all the way around. This is the length of the outside red square. Since the border is 12cm wide, to find the length of the black square inside, you have to subtract 90cm – 12cm – 12cm (you subtract 12 twice because the border is on both sides). This would make the length of the black square 66cm. You can find the area of the black square now by multiplying the length of the black square (A = 66 x 66 = 4356cm squared). This is the area of the black square. To find the area of the red space, you find the area of the red square and subtract it by the black square. The area of the red square is A = 90 x 90 = 8100cm squared. Therefore 8100 – 4356 = 3744cm squared is the area of the red space and 4356cm squared is the area of the black space.

      For 4, you could redraw the diagram to look like a right angle triangle with 0.8 and 4.8 being the legs. Therefore the cross pole would be the hypotenuse.

      For 10b, you first draw a diagram of the lasagna. It is a rectangular prism. You double each of the dimensions (19cm = 38cm, 24cm = 48cm and 7cm = 14cm). You calculate the volume of this new tray (V = 38 x 48 x 14 = 25536cm cubed). The volume of the original tray that feeds 4 people is V = 19 x 24 x 7 = 3192cm cubed. You divide 25536 by 3192, 25536/3192 = 8. This means the new tray is 8 times larger than the original tray. This means it feeds 8 times as many people. Therefore 8 x 4 = 32 people.

      I hope these solutions make sense. If not let me know. I am going to write these solutions out on a paper anyways and take them at them up at the start of the class on the digital projector. Thanks Dylan.

      Mr. Bawa


  2. Tito says:

    I don’t get question two on the practice test and I am using my sister i pod


    • Mr. Bawa says:

      Hey Tito,
      you didn’t have to do the practice test for homework. If that is what you are talking about then you didn’t have to do #2 for that yet because I have not taught you the volume of a cone or sphere yet. I will check with you tomorrow to make sure which one you were having trouble with. Thank you for contacting me. See you tomorrow.
      Mr. Bawa


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